Chicago White Sox: Three New York Yankees free agents to add

NEW YORK, NEW YORK - JUNE 18: Giancarlo Stanton #27 of the New York Yankees in action against the Tampa Bay Rays at Yankee Stadium on June 18, 2019 in New York City. The Yankees defeated the Rays 6-3. (Photo by Jim McIsaac/Getty Images)
NEW YORK, NEW YORK - JUNE 18: Giancarlo Stanton #27 of the New York Yankees in action against the Tampa Bay Rays at Yankee Stadium on June 18, 2019 in New York City. The Yankees defeated the Rays 6-3. (Photo by Jim McIsaac/Getty Images) /
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Chicago White Sox Yoan Moncada
(Photo by Sarah Stier/Getty Images) /

The Chicago White Sox should look at the New York Yankees free agents.

The Chicago White Sox and the New York Yankees have a lot in common. They are both very talented teams that are pretty close to being true threats to win the World Series. They are probably going to meet in the playoffs at some point as they both have similar goals as they go into the 2021 season. They each have one World Series title since 2005 and they would both like to get one sometime soon.

The White Sox season came to an end after losing in three games to the Oakland A’s. The Yankees were done after a tough five-game series with the Tampa Bay Rays in the ALDS. The Yankees were a little bit more seasoned here in 2020 but going forward, they should be pretty even as long as the White Sox continue to grow.

Like any other team that is as talented as the Yankees, it might be hard to keep everyone. They have some players that are free agents once the World Series is over and the White Sox might want to take advantage. The Yankees are going to really try hard to keep as many people as they can and we all know they can afford to if both parties agree.

The White Sox are going to have to sell themselves in a similar fashion to how the Yankees sell themselves. They play in a world-class city, have a lot of young talent, and are committed to winning baseball games going forward. These are the three Yankees free agents that they should really try to pursue here: